Hello,
I am new to using the Keithley 2002 DMM and am using it to measure the resistance of a thermistor. The resistance at room temperature (22 c) for the thermistor is R= 18,000 ohms.
My understanding is that when I use the 20 kohm range (20,000 ohm) of the Keithley 2002 to measure the 18,000 ohm resistance, the electrical current sourced out by the Keithley 2002 is 89 uA (89E-6 A). This results in a power dissipated on this thermistor of P=i2xR=143 uWatts (1.43E-4 Watts).
In my application I need to keep the power dissipated on the thermistor below 50 uWatts. I was wondering if there is a way to adjust the current sourced out by the Keithley 2002 to make it lower than 89 uA. Ideally lower the current down to 52 uA.
Thank you!
Ron