Haiguang XU

I have solve the problem by replacing code with below
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smua.reset() \n
smua.source.output = smua.OUTPUT_ON \n
smua.source.limitp = 200 \n
smua.sense = smua.SENSE_REMOTE \n
smua.source.levelv = (%1) \n
smua.source.limiti = (%1 /5) \n
v = smua.measure.v() \n
print(v) \n

wait(50)                 // in m-second

smua.source.levelv = (%1) \n
smua.source.limiti = (%1) \n
v = smua.measure.v() \n
print(v) \n
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This method is trying to starting output current from lower value (less than 5A) and then increase to 20A works.

I have a problem with conrtoll my 2651A.
When i use same code to program 2651A as a power source but cause DUT error when current is above 5A.
Please help me to solve the problem. In addition I = 20A works only device is disconnected

\----------------------------------------
smua.reset() \n
smua.source.output = smua.OUTPUT_ON \n
smua.source.limitp = 200 \n
smua.sense = smua.SENSE_REMOTE \n
smua.source.levelv = %1 \n
smua.source.limiti = %1 \n
v = smua.measure.v() \n
print(v) \n
\------------------------------------------
%1 refers to C++ argument which is V = 10 and I = 5 or I = 20