I am planning to perform high voltage (3kV) C-V measurements using the bias tees in the CVU-3K-KIT (see attached), a 2657A SMU and a 4215-CVU. The HV is applied to the DUT through a 2650-RBT-3K bias tee, while the low side is connected through a 2657A-PM-200 protection module and a 2600-RBT-200 bias tee.
I am struggling to understand the operation of the control voltage of the bias tees in the CVU-3K-KIT:
In order to perform capacitance measurements, the AC switch in the bias tee needs to be closed by applying a DC voltage of -10V on the AC input of the bias tee.
How is this DC voltage supposed to be generated? Using the integrated bias in the 4215-CVU or an external voltage source?
In the footnotes of the bias tee modes table (see picture), there is a footnote mention of an external voltage source.
However, an external voltage source would require an additional bias tee, right? So I assume the control voltage is supposed to be generated by the internal bias of the CVU?
I am familiar with the integrated 30V bias tee in the 4215-CVU, but in my thinking this bias voltage is always sourced either on the high (HPOT/HCUR) or low (LPOT/LCUR) side of the DUT, while the other side is at 0V.
In order to perform C-V measurements with these bias tees, I would need to apply -10V at both the high and low connectors.
In the K4200-KXCI reference manual, I found the following CVU command:
:CVU:DCV:OFFSET
which apparently can be used to apply a DC offset to the low terminal.
Does this mean I should use a 10V offset (
:CVU:DCV:OFFSET -10) for the low terminal and set the high terminal also to -10V (
:CVU:DCV -10)?
Are these DC voltages always applied, or just when doing measurements?
In order to perform an open correction, I would still need to be apply -10V to the bias tees in order to close the AC switches.
The documentation on the 2650-RBT-3K and 2600-RBT-200 bias tees is quite sparse, so I would be happy for some more information!